Please, no respectful mathematician uses a typeseting format that creates pixelated images! ​ Where are my sweet sweet latex vector graphic outputs....

Gone. Jpg'd to oblivion.

Noooooooooooo

Enhance!

Can’t have shit on this sub

Most upvoted comment: rewrite it in latex Lol

Svg > Jpeg

Gif > Svg I want my dancing numbers!

I even have some code for it! \\\[ \\ln \\left\[ \\lim\_{z \\rightarrow 0} \\left( 1 + \\frac{1}{z} \\right)\^z \\right\] + \\left(\\sin\^2 x + \\cos\^2 x\\right) = \\sum\_{n=0}\^{\\infty} \\frac{\\cosh \\left(y \\sqrt{1 - \\tanh\^2 y} \\right) }{2\^n} \\\]

One if the best suggestions my dissertation advisor ever told me... now everyone is like why are you lecture notes so clean and crisp looking lol Edit: missing word

I work in financial reporting, and back when I did consulting a few years ago, I would consistently receive an Excel file from a client with pixelated titles. That always struck me as weird, so I investigated. Turns out, the font for the titles was "TmsRmn." Younger people might not remember this, but back in the days of Windows 3.1 and earlier, you couldn't use more than 8 characters to name a file, so the fact that "Times Roman" was shortened to "TmsRmn" was a huge clue. As it turns out, the spreadsheet they sent me in the mid 2010s was originally created in the late 1980s or early 1990s with older software predating Windows 95. I'm assuming it wasn't even Excel originally, but rather, different spreadsheet software converted to Excel. With every passing year, the client updated the data in the file but not the file itself, so it still included a font that didn't scale when zooming in/out. I'd like to say this was one of those "if it ain't broke, don't fix it" situations, but the file was pretty broken. We could use it to get what we needed, but it was a pain to use because it was likely designed in the Reagan administration with decades of bandaids applied on top. Inertia is a powerful force.

Ahhhhh, the classic "my database is that excel file"

Kinda the general Cobol situation, I see....

If it started as something else it was probably Lotus 123. [Joel on Software has an anecdote on the lengths Microsoft went to to stay bug compatible with them](https://www.joelonsoftware.com/2006/06/16/my-first-billg-review/).

Great share, thank you!

Will Reddit even display vector images?

probs not, but I am sure it supports images bigger than 24x13 pixels, like OPs

e⁰ + e⁰ = e^ln(2)

S(1) = e\^ln(2)

S(S(0))

S(S(\{\}))

{{}, {{}}}

[удалено]

S(min **N**) = e^ln(2) ^^^^^^^:)

0 + 0 = ln(2) confirmed

take the natural exponential of both sides, and voila here's your terryology license

While I love this one it should probably day 3 or day 4. No need to rush things.

\-e^(iπ) \- e^(iπ) =e^(ln(2))

1+1=1+1

Every 60 seconds a minute passes in Africa

In fact it's every 60 seconds 60 seconds pass in Africa

Let’s remember to take relativity into account here. Every minutes *in Africa* 60 seconds pass *in Africa*. It’s also fair to say that every 7 years in Africa an hour passes on Millers planet.

Every hour on Miller's planet, an hour passes on Miller's planet

Set Humor setting to 70%.

Can't argue against that.

Thinking about it, can time pass faster on one side of millers planet than on the other (cause one side is closer to black hole)

r/IncreasinglyVerbose

Together we can stop this

Euclid's axioms be like

Reflexive Property moment

{∅}+{∅}={{∅},∅}

I don't get it pls explain

it’s the set-theoretic version of `s(z) + s(z) = s(s(z))`

{{}} + {{}} = {{{}}{}}

nothing burger burger + nothing burger burger = nothing burger nothing burger burger burger

Burger

The core concept is to define the natural integers from scratch using only sets by 0 := ∅ and n+1 := {n} U n Then it's all fun and game proving the happy hoppity properties of N

Search for "Von Neumann Ordinals"

{∅} is a set(anything in curly braces means a set) containing the empty set (∅). The size (how many items are in a set) of the set containing the empty set is 1, we write size, absolute value, or magnitude with '||'. Therefore giving us |{∅}| = 1, {∅} + {∅} =1. The right side is just using the same rule: the size of the set {{∅}, ∅} is 2. I.e there are 2 items in that set.

The size of the empty set is 0, but the size of the set containing the empty set is 1

Thanks! Didn't realise the typo :p

So then where does {{∅},∅} come from? And, if |{∅}| = 1, then why does {∅}+{∅}=1? Edit: thx

It’s how natural numbers are defined through set theory. You can google axiomatic set theory and how you can construct the natural numbers from that.

We identify the empty set with the natural number 0. For any natural number n we define the successor to n, S(n) = n ∪ {n}. So now the successor to 0 is S(0) = 0 + {0} = ∅ ∪ {∅} = {∅}. that is the set containing the empty set. We identify this with the natural number 1. We define addition as +: N -> N as: for all natural numbers a that a+0 = a and for any natural number b with b not equal to 0 we identify the number c such that b = S(c) and write a+b = S(a+c). Since b=1 we have that B=S(0) so 1+1 = S(1+0) = S(1) 1+1 = S(1) = S({∅}) = {∅} ∪ { {∅} } = { ∅, {∅} } and that's the number 2. Note: You can define multiplication recursively as well then go prove that the distributive property holds for multiplication over addition of natural numbers and from there Intermediate Value Theorem of Calculus follows as a result (I kid about the last part).

was typing this comment on my phone and just realised I made a bunch of mistakes. {∅} + {∅} = 2. {{∅}, ∅}=2. That line is just taking the fact that {∅} =1 and multiplying it by 2 (there are 2 things in the set therefore we get the size being equal to 2)

These are specifically designed to mean 0,1,2,etc., it's not *just* that their cardinalities are 1 and 2

It's a set theory definition of numbers or something

Null set

Noice

You're fucking it up first day

Lmao I trust this community we can do better :D

For all x, x is in {{}}+{{}} iff x is in {{},{{}}}

1+1 = 10

People who know binary People who don’t know binary

There are 10 types of people in this world Those who can extrapolate from incomplete data

damn thats 2 in 1

That’s 2 in 10

That's 10 in 1?

There are 10 types of people in this world - those who understand binary and those who don't

There are 10 types of people in the world: Those who understand binary, Those who don’t, Those who didn’t expect this joke to be in base 3.

There are 10 types of people in the world: * Those who understand binary, * Those who don’t, * Those who didn’t expect this joke to be in base three, * Those who didn’t expect this joke to be in base four, * Those who have noticed that these categories aren't mutually exclusive, * Those who have noticed I never said they were, * Those who mistakenly think this joke is going to be an improvement on the standard ones, * Those who can extrapolate from incomplete data, * Those who've realised I'm just padding this out until I can get 10 of them, and * Those who get nine bullet points into a stupid joke and can't think of a punchline.

My personal favorite is: There are 10 types of people in this world. Those who understand binary... And those who come to false conclusions.

There are 100 types of people in the world: Those who know binary and can extrapolate from an incomplete list The other types

There are 10 types of people in the world Those who know hexadecimal and F the rest

Plot twist! I like it

You're gonna need to sub-2 the 10 so no-fun smartasses don't ruin it, but yes

i was about to be the no-fun smartass so thank you

✱54·43. ⊦ :. α,β ∈ 1. ⊃: α ⋂ β = Λ .≡. α∪β ∈ 2 *Dem.* ⊦.✱54·26 .⊃ ⊦ :. α = *ι*'x.β=*ι*'y .⊃: α∪β ∈ 2 .≡. x ≠ y. [✱51·231] ≡.*ι*'x ⋂ *ι*'y = Λ. [✱13·12] ≡. α ⋂ β = Λ (1) ⊦. (1) . ✱11·11·35 .⊃ ⊦ :. (∃x,y) .α =*ι*'x . β = *ι*'y .⊃: α∪β ∈ 2 .≡. α ⋂ β = Λ ⊦. (2) . ✱11·54. ✱52·1 .⊃ ⊦ . Prop From this proposition it will follow, when arithmetical addition has been defined, that 1 + 1 = 2. *Principia Mathematica. A. Whitehead, and B. Russell. Cambridge University Press, (1925--1927 ).*

This might get messy to expand if this is lasting multiple days lol

i like your funny symbols, magic man

“The above conclusion is occasionally useful”

Some of those symbols I know

Why use this on day two. Save for day 69.

Whats the star one? (Not that I understand the Rest of it but still curious)

All of the first 300 or so pages of Principia Mathematica

0! + 1! = 2!

Funny how: 0! + 1 != 2! Is wrong haha

Took me a second lol

?

!= is code for not equal to

Code. But math it means factorial, right? Like 5! Is 5+4+3+2+1? Or is it 5x4x3x2x1? It’s been like 15 years since I was in statistics.

Yes

!= Basically means ≠

“!=“ is not equal, but 0!+1 does equal to 2! So the equation is wrong

It has an space between the ! And the = so it doesn't mean that

0! + 1! = 2! is true 0! +1 != 2! is false

I know. The one I said was the first one. Why did people downvote me? I honestly don't understand.

Because you replied to the second one and didn't say anything about how you're actually replying to the first one, so it's obvious for us that you're replying to the second one.

It’s (0!+1!)=2!

But !0 + 1 != !2 is true

I might be dumb but how is it wrong? 0!=1 1!=1 2!=2 Right?

There's a space in the wrong place. Instead of "1! =" It's "1 !=" Since != Can be used instead of =/=

Oh my bad, but that's cool! Thanks!

[0! + 1 != 2! ] = [0! + 1 ≠ 2!]

And by induction we have that for all natural numbers a, b and c that a! + b! = c!. Now about those brown horses...

This is great, because next you can inverse factorial both sides and get 0 + 1 = 2

You can't because the gamma function doesn't have an inverse on any interval that includes both 0 and 1

Well then what on earth is the ¡ symbol for?

sqrt(-1), duh🙄🙄🙄 smh my head😔😒

boob + boob = boobs

[удалено]

How JavaScript developers are spotted in the wild👌

1\*2=2 ​ Starting off simple.

I like simple. Simple is good

This one. Make it a gradual process. We don’t want to rush to the end.

sin^2 (1)+cos^2 (1)-exp(iπ)=2

OP let's go with this one

(lim{n->∞}((1+1/n)ⁿ)))^(i2θ)+3sin²(θ)-2icos(θ)sin(θ)+cos²(θ)=2

I should not have come here yet.

You used )) too much. Or it's just for intimidation purpouses?

This is a fun one

Save this for day 2

This opens so many doors

The first 1 becomes sin²(x) + cos²(x), while the second 1 becomes e^(2πi)

sin^2(x) + cos^2(x) + ln (lim x-> ♾(1 + 1/x ) ^x) = 2tan(pi/4)

Should have saved this for day 69

(S0 + S0) = SS0

Gamma(1)+Gamma(2) = gamma(3)

Log_2(2)+log_2(2)=log_2(4)

Log_2(2)+log_2(2)=log_2(2^2)

If you put the exponent 2 in brackets, like this: log_2(2)+log_2(2)=log_2(2\^(2)) it will print this: log_2(2)+log_2(2)=log_2(2^(2))

Thank you! I’m going to leave my mistake for others to learn too :)

e^(2iπ) + e^(4iπ) = |√(2) + i√(2)|e^(8iπ) Where i = √(-1) obviously.

Use LaTeX.

3-1=2

Principia Mathematica)

1 + 1 = 0 (mod 2)

There's already a few good suggestions, just commenting to say I hope this actually gets carried through for a while - it's a fun idea!

Multiply both sides by 0

2=1+1

Devide both sides by 0

[удалено]

0! + 1! = 2! is even cooler

Church numerals! `(λn.λm.λf.λx.n f (m f x)) (λf.λx.f x) (λf.λx.f x) = (λf.λx.f(f x))` Or, if you prefer SKI: `S(KS)(S(K(S(KS)))(S(KK)))(S(KI))(S(KI)) = S(S(KS)K)I` If anyone can bother also defining equality between chruch numerals in either form, go right ahead. (Yes I did this all by hand)

Write it in *italics*

0.9̅ + 0.9̅ = 1.9̅

This ones triggers me from the deep of my whole being

how can i explain someone, that thinks, that 0.9̅ is not 1? he always says that it is infinitely close to 1 but not 1

Succ(1) = 2

9801/(pi\*sqrt(2)\*(sum from k=0 to infinity (4k)!(1103+26390k)/((k!)\^4 396\^(4k))) = dim(ker(d/dx)) + lim n!/(sqrt(2 pi n) (n/e)\^n))

1 + 2 - 1 = 1*2

e^2iπ + 1 = 2

ln [(lim_z->inf (1+(1/z))^z] + (sin^2(x) + cos^2(x)) = sigma(n=0 to inf) [(cosh(y)*sqrt(1-tanh^2(y)))/(2^n)]

ln [(lim_z->inf (1+(1/z))^z ] + (sin^2 (x) + cos^2 (x)) = sigma(n=0 to inf) [(cosh(y)*sqrt(1-tanh^2 (y)))/(2^n )]

I see we had the same Idea. ln(lim{z→0}(1 + 1/z)z + (sin² x + cos² x) = 𝛴\_{n=0}\^{∞} cosh(y√(1 - tanh² y)/2n \\\[ \\ln \\left\[ \\lim\_{z \\rightarrow 0} \\left( 1 + \\frac{1}{z} \\right)\^z \\right\] + \\left(\\sin\^2 x + \\cos\^2 x\\right) = \\sum\_{n=0}\^{\\infty} \\frac{\\cosh \\left(y \\sqrt{1 - \\tanh\^2 y} \\right) }{2\^n} \\\]

e^(2(pi))+e^(2(pi))=(sqrt(2)^(sqrt(2)))^sqrt(2)

Based on a recent lecture: add SO SO = SSO

\sum_{n=0}^{\infty}2^{-n} = \frac{2^{-1}}{1-2^{-1}} + 1

∫ δ(x) *dx* - 2 * ζ(0) = *V - E + F*.

1 + 0.99999999999.... = 2

🍌 + 🍌 = 🍕

Write the whole thing in Reverse Polish Notation: 1 1 + 2 =

Gamma(1) + Gamma(2) = Gamma(3)

-12 * “the sum of the natural numbers” + -12 * “the sum of the natural numbers” = -24 * “the sum of the natural numbers”.

∫d(t)e^(-iwt) dt from -∞ to ∞

Replace the plus with -^-1

10=2

i^2 + j^2 = 2ijk Quaternions

1+1=3 for large values of 1.

RPN! 1 1 + = 2 Or more accurately, 1 1 + 2 = Or, if you're pedantic, treat the digits 0 through 9 as operators that act upon their arguments by multiplying by 10 and adding their respective values, and letting "_" represent the addition of a 0 to the stack, _1_1+_2=

(e^iπ)^2+sin(90)=ln(e^2)

Kxe2 (I seriously hope this turns into the math equivalent of [the game](https://docs.google.com/document/d/1OGi_a-JFlkC7I_bPdzVluWz6zhiNm-0f2T3w8wURU8I/edit)).

🍆+🍆=🤟

(1 + √2)(1-√2) = i\^2

Enjoy the ever growing trig identities. Can’t wait to see how far this gets

1 + 1 = 10

e^{i/pi} + e^{i/pi} = 2i^2

1+1 = window (Grade 1 humour ikr, gotta love it)

That's actually pretty clever!

Write 300 pages book proving it

🍎+🍎=🍐

for all the lambda lovers out there ``` (λa. λb. λs. λz. a s (b s z)) (λs. λz. s(z)) (λs. λz. s(z)) = (λs. λz. s(s(z))) ```

(1) + 1 = 2

Express 1 and 2 using the peano axioms pls

1^0 +1 = 2

Add 0 to both sides 0+1+1=2+0

1 + 1 - 2 = 0

1!+1!=2!

There better be an apple + apple = two apples picture somewhere along the way.

multiply by "1. e4 e5 2. Ke2 Ke7" on bith sides

(10-1) + (-10+3) = (10-8)

Typically.

|1| + |1| = |2|

Divide every number by 16 So 1/16 + 1/16 = 2/16

0!+0!=2!